Question

\[ B_{1}=\left(\begin{array}{lll} 1 & 0 & 2 \\ 1 & 1 & 1 \\ 3 & 1 & 1 \end{array}\right) \] a) compute \( \operatorname{det} B_{1} \) b) \( \exists B_{1}^{-1} \) ? Why? c) find \( B_{1}^{-1} \) if \( f B_{1}^{-1} \). If \( B^{-1} \) find \( \left(I+B_{1}\right)^{-1} \) by 2 ways,

          \[
B_{1}=\left(\begin{array}{lll}
1 & 0 & 2 \\
1 & 1 & 1 \\
3 & 1 & 1
\end{array}\right)
\]
a) compute \( \operatorname{det} B_{1} \)
b) \( \exists B_{1}^{-1} \) ? Why?
c) find \( B_{1}^{-1} \) if \( f B_{1}^{-1} \).

If \( B^{-1} \) find \( \left(I+B_{1}\right)^{-1} \) by 2 ways,

B1=(
1 0 2

1 1 1

3 1 1
)

a) compute det B1
b) ∃ B1^-1 ? Why?
c) find B1^-1 if f B1^-1.

If B^-1 find (I+B1)^-1 by 2 ways,

Added by Jes-S M.

Precalculus

John W. Coburn 2nd Edition

Chapter 8

Instant Answer

Solved by Expert Linda Hand

Step 1

Given: \[ B_1 = \begin{pmatrix} 1 & 0 & 2 \\ 1 & 1 & 1 \\ 3 & 1 & 1 \end{pmatrix} \] The determinant of a 3x3 matrix \( A = \begin{pmatrix} a & b & c \\ d & e & f \\ g & h & i \end{pmatrix} \) is given by: \[ \det(A) = a(ei - fh) - b(di - fg) + c(dh - eg) Show more…

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\[ B_{1}=\left(\begin{array}{lll} 1 & 0 & 2 \\ 1 & 1 & 1 \\ 3 & 1 & 1 \end{array}\right) \] a) compute \( \operatorname{det} B_{1} \) b) \( \exists B_{1}^{-1} \) ? Why? c) find \( B_{1}^{-1} \) if \( f B_{1}^{-1} \). If \( B^{-1} \) find \( \left(I+B_{1}\right)^{-1} \) by 2 ways,