Bacteria increase according to the formula $B(t) = Ce^{kt}$, where C and k are constants, and B(t) gives the number of bacteria as a function of time t in min. At time t = 0, there are $10^6$ bacteria. How long will it take before they increase to $10^7$ if it takes 12 min to increase to $2 \times 10^6$?
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Step 1: We are given the formula for the growth of bacteria as B(t) = Ce^(kt), where C and k are constants. Show more…
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