00:01
Hello students, here this question and parents reaction of aluminum hydroxide with hcl is given, we have to balance the equation and find the coefficient for the water.
00:10
So here we can say that in reaction side, the number of aluminum atom is 1, of that of the oxygen atom is 3 and the hydrogen atom is 4, where the chlorine atom is equal to 1.
00:20
But in the product said aluminum atom is 1, the oxygen atom is 1, and that of the hydrogen atom is 2, where the chlorine atom is 3.
00:30
So in order to balance this first we can multiply the number of chlorines in the reaction side with 3 to balance it with the chlorine on the product side.
00:40
So he will get us aluminum hydroxide plus the seal comes with the hcl so it will become 3 hcl giving aluminum chloride plus h2o.
00:56
Then what happens here? the number of aluminum is same here as that of the hydrogen here becomes how much 6 were the hydrogen here it is only 2 and the oxygen here is 3 and the oxygen on the product side is only 1 all others are balanced so now to balance this what we can do is we can multiply the number of atoms in the product side with 3 and then we will find the equation and as a result we will get a balance reaction like aluminum hydroxide plus 3hcl that will result in the formation of 1 mole of aluminum chloride with 3 moles of h2o...