Balance the following redox reaction under acidic conditions Cr2O72- (aq) + I- (aq)--> I2 (s) + Cr3+ (aq)
Added by Harold S.
Step 1
Oxidation half-reaction: $I^-$ (aq) $\rightarrow$ $I_2$ (s) Reduction half-reaction: $Cr_2O_7^{2-}$ (aq) $\rightarrow$ $Cr^{3+}$ (aq) Show more…
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