00:01
In this problem of frequency distribution, we have to first find construct the relative frequencies to gram for the given data set using four eight classes.
00:15
So let's find the class width.
00:18
First, class width is equal to range divided by number of classes.
00:33
So here the range is 104 minus 61 divided by local.
00:44
Classes, eight.
00:46
So if we select the convenient value, the next convenient value, to come around five point simply so we can just move to six.
01:00
Now let's construct a frequency distribution table in order to construct the graph.
01:24
So here the class starts with 61.
01:38
You'll add 5 so that the classes does not overlap.
01:43
So 61 to 66, 66 to 67 to 66 plus 6, 72, 73 to 79, 79 to 84, 85 to 90, 91 to 91 to 96, 97 to 100 to 80, 100 to 80, 80, 488.
03:17
So let's find out frequency.
03:27
So 61 to 66.
03:35
1 .67 to 72.
03:43
1 .2 .3.
03:56
73 to 78.
04:07
1 .2.
04:08
3.
04:10
4.
04:15
5.
04:16
6.
04:25
79 to 84.
04:32
1 .2 .3.
04:41
5.
04:42
5...