Question

A bar of mild steel carries an axial pull of 10 kN and a transverse shear force of 5 kN. Taking the elastic limit in tension as 240 MPa, a factor of safety of 3, and Poisson's ratio of 0.3, calculate the diameter of the bar if the criterion is (i) Maximum principle stress theory, (ii) Maximum strain energy theory.

Name: bar of mild steel carries an axial pull of 10 kn and a transverse shear force of 5 kn taking the elastic limit in tension as 240 mpa a factor of safety 3 and poissions ratio 03 calculate the 45597
Uploaded: 2023-01-23T16:20:20-08:00
Duration: 2 min 10 s
Channel: Sri K
Description: bar of mild steel carries an axial pull of 10 kn and a transverse shear force of 5 kn taking the elastic limit in tension as 240 mpa a factor of safety 3 and poissions ratio 03 calculate the 45597

          A bar of mild steel carries an axial pull of 10 kN and a transverse shear force of 5 kN. Taking the elastic limit in tension as 240 MPa, a factor of safety of 3, and Poisson's ratio of 0.3, calculate the diameter of the bar if the criterion is (i) Maximum principle stress theory, (ii) Maximum strain energy theory.

Added by Montserrat H.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Sri K

01/23/2023

Step 1

The elastic limit in tension is given as 240 MPa, and the factor of safety is 3. Therefore, the allowable stress (\( \sigma_{\text{allowable}} \)) is calculated as: \[ \sigma_{\text{allowable}} = \frac{240 \, \text{MPa}}{3} = 80 \, \text{MPa} \] Show more…

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A bar of mild steel carries an axial pull of 10 kN and a transverse shear force of 5 kN. Taking the elastic limit in tension as 240 MPa, a factor of safety of 3, and Poisson's ratio of 0.3, calculate the diameter of the bar if the criterion is (i) Maximum principle stress theory, (ii) Maximum strain energy theory.