Based on an analysis of sample data, an article proposed the pdf $f(x) = 0.65e^{-0.65(x - 1)}$ when $x ge 1$ as a model for the distribution of $X = $ time (sec) spent at the median line. (Round your answers to three decimal places.) (a) What is the probability that waiting time is at most 8 sec? More than 8 sec? at most 8 sec more than 8 sec $P(X le 8) = $ $P(X > 8) = $ (b) What is the probability that waiting time is between 4 and 6 sec?
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Based on an analysis of sample data, an article proposed the pdf f(x) = 0.65e^(-0.65(x - 1)) when x ≥ 1 as a model for the distribution of X = time (sec) spent at the median line. (Round your answers to three decimal places.) (a) What is the probability that waiting time is at most 8 sec? More than 8 sec? at most 8 sec P(X ≤ 8) = more than 8 sec P(X > 8) = (b) What is the probability that waiting time is between 4 and 6 sec?
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