4. Alleles A/a and B/b are alleles from two different loci. A cross between AaBb x AaBb will produce offspring with expected phenotypic ratio of 9:3:3:1. Assuming the results in Table 5 were obtained from a dihybrid cross. Complete Table 5 and calculate X². Table 5. Results of dihybrid cross. Genotype | Observed Number (O) | Expected Number (E) | Deviation (O - E) | (O - E)² | (O - E)²/E A-B- | 429 | | | | A-bb | 81 | | | | aaB- | 89 | | | | aabb | 41 | | | | Total | 640 | | | | X² = The expected probability of aabb = ______ Degrees of freedom (df) = ______ p-value range = ______ You reject / fail to reject the null hypothesis of the chi-square test. (circle the answer)
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Since the phenotypic ratio is 9:3:3:1, we can calculate the expected numbers as follows: Total offspring = 640 Expected numbers: A-B-: 9/16 * 640 = 360 A-bb: 3/16 * 640 = 120 aaB-: 3/16 * 640 = 120 aabb: 1/16 * 640 = 40 Now, we can complete the table: | Show more…
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A dihybrid cross is performed in Drosophila - one parent is heterozygous for both genes (B/b ; F/f) and is test-crossed with a homozygous recessive type (b/b ; f/f). (where B = black body; b = brown body; F = forked bristles; f = unforked bristles.) The results are: black, forked 230 black, unforked 210 brown, forked 240 brown, unforked 250 How many degrees of freedom would you use in this case? What would be the expected number for each phenotype? Calculate the chi-square value for this cross. Assuming p=0.05, what critical value would you use to compare the calculated chi-square value against? Do you reject or not reject the expected ratio in this case
Sri K.
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