Question

\[ \begin{array}{l} 3-\frac{1-\frac{1}{3}}{2+\frac{1}{1}}=? \quad \frac{3^{-2} \cdot(-3)^{4}}{3^{0}}=3 \\ \left.\sum_{\sqrt[3]{0,027}-\sqrt{0,09}+\sqrt[3]{-125}=7}^{1-\frac{1}{3}} \right\rvert\, \frac{3}{\sqrt{3}}-\frac{2}{\sqrt{3}-1}=? \end{array} \] (6) \[ 3\left(x^{2}-2\right)+5 x=3 x+2 \] (7) \[ x+4=2 x-2 \] (6) \[ \begin{array}{l} 2 x-3 y=10 \\ x+y=-3 \end{array} \] (8) S1-) \( A\left[\begin{array}{cc}1 & 3 \\ -1 & 2\end{array}\right]_{2 \times 2} \) ife \( A^{2}= \) ? S2-) Asogida limitlen yuntarindan ver, len nottolardan bulun \[ 9-\lim _{x \rightarrow 3^{-}} \frac{x^{2}-2 x-3}{3-x}=? \quad b \lim _{x \rightarrow \infty} \frac{4 x^{2}+1}{3 x^{2}-2 x+2}=? \] S3-) \( f(x)=2 x^{3}+x^{2}-3 x+2 \), Sef \( (1)= \) ? 5) \( f(x)=\left(x^{2}+1\right) \cdot(3 x-4), \delta \frac{d f(x)^{\prime}}{d x}= \) ? \[ \begin{array}{l} \text { S4 }=f(x)=\frac{x^{2}+1}{2 x-1} \text {, Se } f(1)=? \quad \text { S }=y=3 a^{2}+2 a-1 \\ b \Rightarrow f(x)=\left(2 x^{2}+3 x\right)^{3} \text { ise } f(x)=? \\ \text { S5 }=y=\cos ^{2}\left(x^{3}+1\right) \text {, se } y=\text { ? } \frac{d y}{d x}=\text { ? } \\ S_{6}=f(x)=x^{2}+3 x-4 \text { ve } g(x)^{0}=x^{3}+2 \text { ise }(\text { fog })(1)=\text { ? } \end{array} \]

          \[
\begin{array}{l}
3-\frac{1-\frac{1}{3}}{2+\frac{1}{1}}=? \quad \frac{3^{-2} \cdot(-3)^{4}}{3^{0}}=3 \\
\left.\sum_{\sqrt[3]{0,027}-\sqrt{0,09}+\sqrt[3]{-125}=7}^{1-\frac{1}{3}} \right\rvert\, \frac{3}{\sqrt{3}}-\frac{2}{\sqrt{3}-1}=?
\end{array}
\]
(6)
\[
3\left(x^{2}-2\right)+5 x=3 x+2
\]
(7)
\[
x+4=2 x-2
\]
(6)
\[
\begin{array}{l}
2 x-3 y=10 \\
x+y=-3
\end{array}
\]
(8)

S1-) \( A\left[\begin{array}{cc}1 & 3 \\ -1 & 2\end{array}\right]_{2 \times 2} \) ife \( A^{2}= \) ?
S2-) Asogida limitlen yuntarindan ver, len nottolardan bulun
\[
9-\lim _{x \rightarrow 3^{-}} \frac{x^{2}-2 x-3}{3-x}=? \quad b \lim _{x \rightarrow \infty} \frac{4 x^{2}+1}{3 x^{2}-2 x+2}=?
\]

S3-) \( f(x)=2 x^{3}+x^{2}-3 x+2 \), Sef \( (1)= \) ?
5) \( f(x)=\left(x^{2}+1\right) \cdot(3 x-4), \delta \frac{d f(x)^{\prime}}{d x}= \) ?
\[
\begin{array}{l}
\text { S4 }=f(x)=\frac{x^{2}+1}{2 x-1} \text {, Se } f(1)=? \quad \text { S }=y=3 a^{2}+2 a-1 \\
b \Rightarrow f(x)=\left(2 x^{2}+3 x\right)^{3} \text { ise } f(x)=? \\
\text { S5 }=y=\cos ^{2}\left(x^{3}+1\right) \text {, se } y=\text { ? } \frac{d y}{d x}=\text { ? } \\
S_{6}=f(x)=x^{2}+3 x-4 \text { ve } g(x)^{0}=x^{3}+2 \text { ise }(\text { fog })(1)=\text { ? }
\end{array}
\]

3-(1-(1)/(3))/(2+(1)/(1))=? (3^-2·(-3)^4)/(3^0)=3
.∑√(0,027)-√(0,09)+√(-125)=7^1-(1)/(3)| (3)/(√(3))-(2)/(√(3)-1)=?

(6)

3(x^2-2)+5 x=3 x+2

(7)

x+4=2 x-2

(6)

2 x-3 y=10

x+y=-3

(8)

S1-) A[
1 3
-1 2
]2 × 2 ife A^2= ?
S2-) Asogida limitlen yuntarindan ver, len nottolardan bulun

9-limx → 3^-(x^2-2 x-3)/(3-x)=? b limx →∞(4 x^2+1)/(3 x^2-2 x+2)=?

S3-) f(x)=2 x^3+x^2-3 x+2, Sef (1)= ?
5) f(x)=(x^2+1) ·(3 x-4), δ(d f(x)^')/(d x)= ?

S4 =f(x)=(x^2+1)/(2 x-1), Se f(1)=? S =y=3 a^2+2 a-1

b ⇒ f(x)=(2 x^2+3 x)^3 ise f(x)=?
S5 =y=cos ^2(x^3+1) , se y= ? (d y)/(d x)= ?

S6=f(x)=x^2+3 x-4 ve g(x)^0=x^3+2 ise ( fog )(1)= ?

Added by Ahmet

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