\( \begin{array}{l}2 a+3 b-c=11 \\ 19 a+14 b-3 c=43-(2) \\ -11 a-2 b-c=1-(3)\end{array} \)
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Equation 2: \(19a + 14b - 3c = 43 - 2\) Simplify to: \(19a + 14b - 3c = 41\) Equation 3: \(-11a - 2b - c = 1 - 3\) Simplify to: \(-11a - 2b - c = -2\) Now the system of equations is: 1. \(2a + 3b - c = 11\) 2. \(19a + 14b - 3c = 41\) 3. \(-11a - 2b - c = -2\) Show more…
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