Question

Below is a sketch of the region bounded by the curve $x = an(frac{pi y}{4})$, the line $x = 0$, and the line $y = 1$. (Click on the graph to enlarge it.) A solid is obtained by rotating this region about the y-axis. A cross-section of the solid perpendicular to the y-axis is a circular disk with radius $r = g(y)$ (because the radius depends on y) and area $A(y) = pi[g(y)]^2$. What are the radius and area of the disk at y? $r = g(y) = an(frac{pi y}{4})$ $A(y) = pi( an(frac{pi y}{4}))^2$ The volume of the solid is then given by $V = int_c^d pi[g(y)]^2 dy$. Find the following c = 0 d = 1 V =

          Below is a sketch of the region bounded by the curve $x = 	an(frac{pi y}{4})$, the line $x = 0$, and the line $y = 1$.
(Click on the graph to enlarge it.)
A solid is obtained by rotating this region about the y-axis. A cross-section of the solid perpendicular to the y-axis is a circular disk with radius $r = g(y)$ (because the radius depends on y) and area $A(y) = pi[g(y)]^2$. What are the radius and area of the disk at y?
$r = g(y) = 	an(frac{pi y}{4})$
$A(y) = pi(	an(frac{pi y}{4}))^2$
The volume of the solid is then given by $V = int_c^d pi[g(y)]^2 dy$. Find the following
c = 0
d = 1
V =

$Below is a sketch of the region bounded by the curve x = an(fracpi y4), the line x = 0, and the line y = 1. (Click on the graph to enlarge it.) A solid is obtained by rotating this region about the y-axis. A cross-section of the solid perpendicular to the y-axis is a circular disk with radius r = g(y) (because the radius depends on y) and area A(y) = pi[g(y)]^2. What are the radius and area of the disk at y? r = g(y) = an(fracpi y4) A(y) = pi( an(fracpi y4))^2 The volume of the solid is then given by V = intc^d pi[g(y)]^2 dy. Find the following c = 0 d = 1 V =$

Added by Sharon D.

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