\frac{x}{x^2-4} + \frac{3}{x+2} = \frac{x}{x-2} x^2 - x + 4 = 0 x^2 - 2x - 6 = 0 x^2 + x + 4 = 0 x^2 - 2x + 6 = 0 x^2 + 2x + 6 = 0 x^2 + x - 4 = 0
Added by Cole H.
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Step 1: Multiply both sides of the equation by (x^2 - 4)(x+2)(x-2) to clear the denominators. Show more…
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