00:01
Here in this quotient we are given the velocity of the blood in first section which is represented by v1 that is 0 .15 meter per second and we are given that the diameter of the second section is 80 % of 80 % of the first section.
00:40
So here what we can say that let's say d1 is the diameter of first section so we can write it as d2 that is the diameter of second section is equals to the 80 % of the first section that is 0 .80 multiplied by the d1.
01:04
So from here we can say that since the cross sectional area a is directly proportional to the square of the diameter that is a is directly proportional to the d square so we can say that a2 from here is equals to the 0 .80 raised to the power 2 and a1 from here is equals to the 0 .64 of so a2 not a1 is equals to the 0 .64 of a1.
01:39
So from here we are using the equation that in this quotient we are using the continuity equation which states that the volume of a flow rate of a fluid in a pipe must be constant that is a1 v1 is equals to a2 v2.
01:57
Let's say this will be the equation number 1.
02:00
So from here we can write it as that v2 from here is equals to a1 v1 divided by the a2.
02:08
So plugging into the values here we are having the value of a1 v1 volume is given that is equals to 0 .15 divided by the a2.
02:19
We are having the value of a2 that is equals to 0 .64 which we just find out that is 0 .64 of a1.
02:26
A1 to a1 got cancelled from here so v2 from here will become equals to 0 .2344 meter per second.
02:37
So this is the value of v2...