00:01
Hello students, we are given by question which we have the concentration of the butane noic acid that is 7 into 10 square minus t molar and the ka of the buttoinoy acid is 2 into 10 square minus 5.
00:14
We have to find the percentage of the ionization.
00:17
So we have a formula that alpha is equal to under root ka 5c.
00:22
So now we have to put the value in the formula and that is under root ka of the butaneoic acid.
00:30
Is 2 into 10 square minus 5 divided by the concentration of the bickoid acid is 7 into 10 10 square minus 3 and when we calculate it alpha is equal to 0 .0 5334 now we have to find the alpha in the percentage so we have to multiply it by 100 so it is 0 .0534 into 100 and that is equals to 5 .34 percent so the final answer of the first part of the question is that the person is that the of ionization is equal to 5 .34%.
01:07
Now we move to the second part of the question.
01:10
In which we have the concentration of acid and the concentration of salt.
01:15
We have to find the percentage of the ionization.
01:18
So we have the formula that percentage of the ionization is equal to 10 into rastity power ph minus p .k .a.
01:29
Divided by 10 is to the power ph minus pka plus 1 into 100.
01:38
Now we have to put the value in the formula.
01:42
So first we have to find the pca and ph also.
01:47
So we have to find the ph by henderson equation and that is ph is equal to pca plus log concentration of salt divided by concentration.
01:59
Concentration of acid.
02:01
Now we have to find the pca as we know that pka is equal to minus log of k .a...