00:01
In this question we need to stay polar form for each coordinate equation here.
00:11
So let's simplify our question for function of t.
00:15
Here it is given that r is green within zero.
00:18
So for our first equation which is y is equal to 10, our polar form for this equation will be as we will consider our equation.
00:29
So now what we will do here? as we have y is equal to 10, we will start our solution by taking our value for polar coordinates as x will be equal to r cos, cost, cost, t.
00:47
And we will take y as equal to r sine t.
00:52
So these are the assumption.
00:54
And now our value for x squared plus y square will be as r squared cos square t, add a by r squared sine square t so we can take r square common from here and this will be as cos square t added by sine square t that is equal to one as for the trigonometric identity so we will have x square plus y square which is equal to r square and then our value in the simplification of y is equal to 10 that will be by sine t is equal to 10 and i'm sorry this is r sine t sorry for this mistake r sine t and here r will be equal to 10 divided by sine t and this implies as r is equal to 10 cosy so here is the solution of first part of the question this is the answer for a part answer of a part now let's move on to the second part of the question.
02:10
So for part b, where we have our equation x square plus y square is equal to 10.
02:15
So again we have r square which is equal to 10 and therefore value for r will be square root 10.
02:23
So this is our solution for b part of the question.
02:27
Once we have taken our value we can put directly to solve all of the parts.
02:33
Now for the next part part c we have x squared plus y square minus 6x is equal to 0...
