C use your equivalent total resistance from part 5b to...

c. Use your equivalent (total) resistance from part 5b to determine the current that flows through the battery and through each resistor. I = V/R I = 50(R1 + R2 + R3) d. Use your currents from part 5c and Ohm's Law to determine the voltages across EACH individual resistor. Hint: You should be using Ohm's Law three different times -- one time for each resistance and its associated current. e. Add up your three voltages from part 5d. How does this sum compare to the battery's voltage? What physics conservation law does this equality demonstrate?

Transcript

00:03 Okay, so it looked like you had some questions on how can we know what the different currents are falling through the system, as well as what's the individual electric potential energy or voltage that's going through each of the resistors.

00:21 And so i set up a bir chart in my class.

00:25 This is how we usually did things.

00:28 So i'm going to separate out my data in this way.

00:34 This is how i taught the students in my classes.

00:37 So the vir chart is just a way of organizing our thoughts into a chart and then seeing what the pattern is.

00:45 So on the left side, i put the three resistors plus the total amount of everything.

00:51 And then on the columns or the voltage, the current, and the resistance for each device, plus the totals.

01:00 So i didn't know what your voltage for your power supply is.

01:05 So i'm making my nine volts and the nine bolt battery.

01:09 So you're not using nine bolts.

01:11 You're using whatever's from your previous part of this homework assignment.

01:17 But i don't have access to that.

01:18 So i'm using nine bolts.

01:21 I also gathered from what you cut and pasted that the resistors are in series with the battery because it looked like the three resistors were added together to find the total amount of resistance.

01:37 And if that's true, then we're in a series.

01:39 So i'm making that guess as all, get guess as well, that we're all in series here.

01:45 And that's my drawing that i have on the left.

01:47 I've got r1, r2, and r3.

01:49 And i know that they add up to 50.

01:52 At least that's what your question has as a reference.

01:58 So i made up numbers.

02:00 I made r1, 5 oms, r2 15 oms, and r3 30 oms.

02:07 And that'll add up the 50 oms if they're all in series with each other, 5 plus 15 plus 30.

02:14 So that's where those numbers came from.

02:17 So imagine v and i are not known yet of those columns, but i do know the total voltage of nine volts and the total resistance of 50.

02:26 Well, i can use oms law, rearrange.

02:28 Range it to solve for the total current flow in a series circuit, nine divided by 50 will give me 0 .18 amps.

02:38 In definition of a series circuit, the current flow must be maintained throughout that loop.

02:47 So whatever current flow is leaving the 9 -volt battery is entering r1 and exiting r1 and entering onto the next device and so on.

02:57 So everywhere in this serious circuit, the current flow is 0 .18, which makes this pretty easy then to find the voltage.

03:06 Voltage is going to be the i times the r...

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