0 \times 10^{-14}$$
Now, we can use this equation to find the missing concentrations for each solution.
Solution A: We are given [OH−] and need to find [H3O+].
$$[H_3O^+] = \frac{K_w}{[OH^-]} = \frac{1.0 \times 10^{-14}}{2.05 \times 10^{-7}}$$
Solution A:
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