Calculate how many grams of potassium sulfate form when 17.3 g of strontium nitrate reacts completely given the following equation: K2SO4 (aq) + Sr(NO3)2 (aq) → SrSO4 (s) + 2 KNO3 (aq)
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Step 1
Given mass of strontium nitrate = 17.3 g Molar mass of strontium nitrate (Sr(NO3)2) = 211.62 g/mol Number of moles = Mass / Molar mass Number of moles = 17.3 g / 211.62 g/mol Number of moles = 0.082 mol Show more…
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