Calculate $\int_{3}^{9} 6x \, dx$, given the following. $\int_{3}^{9} x \, dx = 36$ $\int_{3}^{8} x^2 \, dx = \frac{485}{3}$ $\int_{8}^{9} x^2 \, dx = \frac{217}{3}$ $\int_{3}^{9} 6x \, dx = 216$
Added by Jason M.
Close
Step 1
We are given the following information: 1. $\int_{3}^{9} x \, dx = 36$ 2. $\int_{3}^{8} x^2 \, dx = \frac{485}{3}$ 3. $\int_{8}^{9} x^2 \, dx = \frac{217}{3}$ Step 2: We need to evaluate $\int_{3}^{9} 6x \, dx$. We can use the property of integrals that states Show more…
Show all steps
Your feedback will help us improve your experience
Andrew Noble and 65 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Andrew N.
Calculate the definite integral, given that $$ \int_{1}^{4} x d x=7.5 \quad \int_{1}^{4} x^{2} d x=21 \quad \int_{4}^{5} x^{2} d x=\frac{61}{3} $$ $$ \int_{1}^{5} 6 x^{2} d x $$
Integration
The Definite Integral
If $\int_{-2}^{3} f(x) d x=4, \int_{-2}^{6} f(x) d x=9, \int_{-2}^{3} g(x) d x=2,$ and $\int_{3}^{6} g(x) d x=3,$ then find the values of each definite integral in Exercises $29-40 .$ If there is not enough information, explain why. $\int_{3}^{6} f(x) d x$
Definite Integrals
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD