00:01
The mass is given as mass is 92 .5 grams whereas the initial temperature, initial temperature, which is taken as t1, is 25 degrees celsius and the final temperature, final temperature, t2 is 108 degrees celsius and the specific heat of water of water which is in liquid state is 4 .18 jules per gram degree centigrade at the same time the specific heat of the water in gaseous medium is 2 .03 jules per gram degree and the heat of vaporization heat of vaporization of water in solid state is 2 .260 kilojoule per gram.
01:06
We know that heat q is equal to n, c, delta, t where n is the mass, c is the specific heat and delta t is change in temperature.
01:25
Change in temperature.
01:28
So heat will be equal to mass is 92 .5 grams.
01:33
Multiply the specific heat of the water in liquid state is 4 .18.
01:38
Multiply with delta t2 minus t1, it will be 108 minus 25.
01:46
So we will get heat is 32 .092.
01:51
1 kilojoules.
01:53
As there is the steam is formed that means there will be vaporization...