Calculate the angular momentum of an ice skater spinning at
6.00 rev/s given his moment of inertia is 0.400 kg · m^2.
b) He reduces his rate of spin (his
angular velocity) by extending his arms and increasing his moment
of inertia. Find the value of his moment of inertia if his angular
velocity decreases to 1.25 rev/s.
c) Suppose instead he keeps his arms
in and allows friction of the ice to slow him to 3.00 rev/s. What
average torque was exerted if this takes 15.0 s?