$x^3 = x + 6$
$x^3 - x - 6 = 0$
By observation, we can see that $x = 2$ is a root of the equation, since $2^3 - 2 - 6 = 8 - 2 - 6 = 0$.
So, we can factor the equation as $(x - 2)(x^2 + 2x + 3) = 0$.
The quadratic $x^2 + 2x + 3$ has no real roots, since its
Show more…