00:01
Okay, in order to answer this question, we have to talk about beta oxidation of a fatty acid that has 12 carbons.
00:06
So, let's first see the beta oxidation of a fatty acid that has six carbons, let's suppose, okay? six carbons.
00:17
So, in one cycle of beta oxidation or one round of beta oxidation, you're going to produce one nadh, one fadh2, and also you're going to lose two carbons in the form of acetyl coate.
00:31
And as you may know, acetate co -a can enter the crept cycle, and in each crept cycle, in each cycle of crept cycle you're going to produce 3 in adh, 1 fedh2, and 1 atp or gtp.
00:48
Okay, that is practically atp.
00:49
So this is what you're going to produce in each ground of beta oxidation.
00:54
So after one round, you're going to lose two carbons in the form of acetal co -a, so you're going to have four carbons remaining.
01:02
And this is going to be the last cycle.
01:04
So when you have four carbon, the next cycle is going to be like the last one.
01:09
And you may ask why if you have four carbons, then you need one ground to eliminate these two carbons and another ground to eliminate these two carbons.
01:17
And this is not true because in the next round, you're going to produce also one in adhd, one fadh, and as you're going to lose two carbons, okay, you're going to produce one acetyl co -a here.
01:32
But instead of producing one acetylchase and then you're going to have a main name of carbon.
01:39
So why don't or why not converting these carbons, all of these carbons, this group of two and this group of two, into acetal coa during this reaction because you can do that because practically you're not going to to like to waste time in another ground of bit oxidation to produce another acetal coa because you have also.
02:03
That you are going to have a remaining of two carbons only.
02:05
So in the last ground in resume, okay, you're going to produce two acetyl coate molecules, only in the last ground of beta oxidation.
02:14
It means when you have four carbons, after this, you're going to produce two acetal coate molecule, only in the last ground of beta oxidation.
02:22
So what happens if you have 12 carbons? 1, 2, 3, and so on, and 12 carbons.
02:29
After how many cycles you are going to have 4 carbons? well, you have 12 carbons then you need to lose eight carbons, right? so after four cycles, after four cycles, you're going to lose eight carbons.
02:46
So you're going to have a remaining of four carbons.
02:49
And in this last round, in this last round, you're going to produce one adhd, one fadh2, and two acetyl to a molecules.
03:00
And here, you're going to produce four nadh because you have four cycles, for fadh fadh 2 and 4 atp.
03:13
I'm sorry, for acetal coi.
03:16
Okay, so practically you can add all of this and you're going to have a total of 5 in adh, 5 fadh 2, and 6 acetal coi molecule...