00:01
In the given question, the concentration of oh -i .n is given 1 .8 multiplied by 10 -2 power minus 5 molar.
00:10
We have to find the concentration of h -3 o plus iron and find that whether the given solution is acidic, basic or neutral.
00:18
So first we will find p -o -h, which is equal to minus log of concentration of o -h -ion.
00:27
So we will put the values.
00:29
P -o -h will be equal to minus log of 1 .8 multiplied by 10 -raise -to -power minus 5.
00:38
When we solve this, p -o -h will be equal to 4 .74.
00:44
Now we can calculate the ph as p -h plus p -o -h is equal to 14.
00:51
So, ph will be equal to 14 minus p -o -h, that is 14 minus 4 .74.
00:59
So the ph will be equal to 9 .26.
01:03
When the ph lies between 1 to 7, the solution is acidic.
01:08
When the ph is 7, the solution is neutral...