Calculate the derivative for $h(t) = \frac{t}{(t+5)(t^2+8)}$. (Use symbolic notation and fractions where needed.) $h'(t) = - \frac{3t^2+10t+8}{(t^3+5t^2+8t+40)^2}$ Incorrect Answer
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$h(t) = \frac{t}{(t+5)(t^2+8)} = \frac{t}{t \cdot t^2 + t \cdot 8 + 5 \cdot t^2 + 5 \cdot 8} = \frac{t}{t^3 + 8t + 5t^2 + 40} = \frac{t}{t^3 + 5t^2 + 8t + 40}$. Show more…
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