Suppose 4.08 g of sodium chloride is dissolved in 50. mL of a 0.80 M aqueous solution of silver nitrate. Calculate the final molarity of chloride anion in the solution. You can assume the volume of the solution doesn't change when the sodium chloride is dissolved in it. Be sure your answer has the correct number of significant digits.
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Given: - Mass of NaCl = 4.0 g - Molar mass of NaCl = 58.5 g/mol Moles of NaCl = Mass / Molar mass Moles of NaCl = 4.0 g / 58.5 g/mol Moles of NaCl = 0.0684 mol Show more…
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