0:00
So we have this table.
00:01
What we basically want to do is fill in these gaps with a linear equation.
00:06
So we'll be doing what we've been doing before, and it's telling us that this is a linear equation, so we don't have to worry about checking that, is we're going to take two points, find the slope between them, put it into point slope, simplify down the slope intercept, and then we'll plug in these.
00:22
We'll plug in 67 .5, then we'll plug in negative 44.
00:26
So i'm going to be using the equations y2 minus y1 over x2 minus x1 and y minus y1 is equal to mx minus x1.
00:41
So first things first, let's grab some points.
00:44
So i'm thinking 5 .5, negative 26 and negative 10, 30.
00:53
And so let's call this one our two and this one are one.
00:59
So 30 plus 26 all over negative 10 minus 5 .5.
01:08
So that's going to give us 56 all over negative 15 .5, which because it's a decimal, i'm just going to simplify that out.
01:17
So 56 divided by 15 .5 is equal to, and then we're, rounding to three decimals, so negative 3 .613.
01:30
So that's our slope.
01:32
So let's plug that into this formula.
01:35
So we have y plus 26, and 26 is from the x1y1 that i noted above is equal to.
01:45
I'm going to just placeholder, call our slope m until we fully simplify it, just so that i don't have to write that decimal out.
01:54
X minus x1 and x1 in this case is 5 .5.
02:00
And then i'll continue simplifying this.
02:03
So y plus 26 is equal to mx minus 5 .5m.
02:11
So y is equal to negative 3 .613x minus.
02:30
It's 5 .5 times that number.
02:35
Well, it's going to be plus, actually.
02:37
So it's plus like 19 .871...