Calculate the heat released when 68.0 g of steam at 116.0°C is converted to water at 58.0°C. Assume that the specific heat of water is 4.184 J/g · °C, the specific heat of steam is 1.99 J/g · °C, and ?Hvap = 40.79 kJ/mol for water.
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First, we need to cool the steam from 116.0°C to 100.0°C. q1 = (mass) × (specific heat of steam) × (change in temperature) q1 = (68.0 g) × (1.99 J/g°C) × (100.0°C - 116.0°C) Show more…
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