Calculate the iterated integral. ∫∫(4x^3 - 27x^2y^2) dy dx y=0 x=2 x=3
Added by Samantha H.
Step 1
Step 1: Calculate the inner integral Ivan: \[ Ivan = \int_{1}^{3} (4x^3 - 27x^2y^2) dy \] \[ = 4x^3 \int_{1}^{3} dy - 27x^2 \int_{1}^{3} y^2 dy \] \[ = 4x^3 (y\big|_{1}^{3}) - 27x^2 (\frac{y^3}{3}\big|_{1}^{3}) \] \[ = 4x^3 (3 - 1) - 27x^2 (\frac{3^3 - 1^3}{3}) Show more…
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