00:02
Here in this problem, we have to calculate the ka of a weak acid if a 0 .051 molar acid has a ph of 3 .29 at 25 degrees celsius.
00:14
Here, ph of the acid given 3 .29.
00:19
What is ph? negative log concentration of hydoneum ions and that is 3 .29.
00:30
So we can write log.
00:32
Of hydrogen ion concentration is negative 3 .29.
00:37
So concentration of h .3oplasans will be 10 to the power of negative 3 .29.
00:44
And that is 0 .000 .51 molar.
00:53
Now let's write the dissociation reaction of the acid in water.
01:06
Now let's set up ice table initial concentration of the acid given here 0 .051 molar.
01:16
0 .0 .051 molar and initial products concentration 0.
01:22
Chains concentration say minus x, then air it will be positive x, positive x...