Calculate the lattice energy of NaCl(s) and draw a
BornāHaber cycle. Data: Enthalpy of sublimation of Na(s) = 107.5
kJ/mol 1st ionization energy of Na(g) = 496 kJ/mol Bond
dissociation energy of Cl2(g) = 242.58 kJ/mol 1st electron affinity
of Cl(g) = ā348.57 kJ/mol Standard enthalpy of formation of NaCl(s)
= ā411.2 kJ/mol (ANSWER: ā787.42 kJ/mol)