00:01
Okay, so we're looking to calculate the mass of water produced when 3 .41 grams of butane.
00:08
So butane is c4h10.
00:12
We're looking for combustion, so that's going to give us water plus carbon dioxide.
00:20
So we have to balance the chemical equation.
00:23
I usually say these combustion equations are easiest if we balance in the order of what i say, cho.
00:33
So we're going to balance the carbons first.
00:36
So there's four carbons on the reactant side, so we're going to put a four here.
00:42
There's 10 hydrogen on the reactant side, so we need to put a five here.
00:48
And then we're going to balance oxygen last.
00:51
So we have five times one plus eight gives me 13.
00:56
So i'm going to put a 13 here, but then what we're going to do is we're going to multiply everything by two.
01:04
So two times one is two.
01:06
We're going to keep the 13, and then we're going to take five times two, which means this is going to be 10...