Calculate the molality of a 6.05 M ethanol (C2H5OH) solution whose density is 0.9295 g/mL.
Added by Jaime H.
Step 1
Given: Molarity of ethanol solution = 6.05 M Molar mass of ethanol (C2H5OH) = 46 g/mol Number of moles of ethanol = molarity x volume Number of moles of ethanol = 6.05 mol/L x 1 L = 6.05 mol Show more…
Show all steps
Your feedback will help us improve your experience
Mahendra Rathore and 81 other Chemistry 101 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Calculate the molality of a 3.91 M ethanol (C2H5OH) solution whose density is 0.9509 g/mL. m
Sima S.
Calculate the molality of a 4.17 M ethanol (C2H5OH) solution whose density is 0.9483 g/mL
Adi S.
The density of an aqueous solution containing 10.0 percent of ethanol $\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\right)$ by mass is $0.984 \mathrm{g} / \mathrm{mL} .$ (a) Calculate the molality of this solution. (b) Calculate its molarity. (c) What volume of the solution would contain 0.125 mole of ethanol?
Recommended Textbooks
Chemistry: Structure and Properties
Chemistry The Central Science
Chemistry
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD