00:01
So our hypothetical compound in question has the formula mx, and when it dissolves, it's going to form m plus and x minus, or m2 plus an x2 minus, but basically a one -to -one ratio.
00:13
And then ksp is going to be the product of the ion concentrations.
00:24
It's 1 .27 times 10 to the negative 36.
00:29
And for every one mole of mx that dissolves, you go one mole of m and one mole of x, ion will of x, so that's equivalent to the solubility and that's the solubility.
00:39
So ksp is equal to the solubility squared.
00:47
So in pure aquea solution, s, the solubility is just going to be the square root of 1 .27 times 10 to the negative 36.
00:59
When you do that in your calculator, you get 1 .12 times 10 to the negative 18th, and we'll put the unit is molar.
01:10
For part b, we have 0 .25 molar of mcl2, and it's a 1 -1 ratio with the m.
01:24
So this is 0 .25 molar in m.
01:31
So then we can get the solubility is just going to be how much x dissolves in this.
01:35
So 1 .27 times 10 to the negative 36 is going to be 0 .25 times 0 .25 times...