Calculate the molarity of 15.4 g of sucrose (C12H22O11) in 74.0 mL of solution. [Molar mass of C12H22O11 = 342.3 g/mol]
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Step 1
Given: Mass of sucrose = 15.4 g Molar mass of sucrose = 342.3 g/mol Number of moles = Mass / Molar mass Number of moles = 15.4 g / 342.3 g/mol Number of moles = 0.04499 mol Show more…
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