Calculate the molarity of 161 grams of sucrose, C12H22O11, in 2.60 liters of solution.
Added by Christine J.
Step 1
C: 12 x 12.01 = 144.12 g/mol H: 22 x 1.01 = 22.22 g/mol O: 11 x 16.00 = 176.00 g/mol Total molar mass = 144.12 + 22.22 + 176.00 = 342.34 g/mol Show more…
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