II. Solve the following problems. Show your solutions. 1) Calculate the network's equivalent capacitance. 2) A 300 ?F capacitor separated by a distance of 4.0 mm was charged to a potential difference of 250 V. What is the energy density in its region in terms of Joules/m³? 3) Charges are equal and opposite on two parallel plates. When space was evacuated, the electric field was 2.80 x 10? V/m. When it was filled with a dielectric material, the electric field was 1.20x10? V/m. What is the dielectric constant? What is the material?
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2) The energy density (u) in a capacitor is given by the formula u = 1/2 * ε * E^2, where ε is the permittivity of free space (8.85 x 10^-12 F/m) and E is the electric field strength (V/d). The electric field strength can be calculated as E = V/d = 250V / 4.0mm Show more…
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