Question

Procedure/Obseryations A student studied the enthalpy of neutralization of \( \mathrm{HNO}_{2} \) and \( \mathrm{NaOH} \) by reacting \( 50.0 \mathrm{~mL} \) of \( 2.00 \mathrm{M} \mathrm{HClO}_{4} \) with \( 50.0 \mathrm{~mL} \) of \( 2.00 \mathrm{M} \mathrm{NaOH} \) in a calorimeter. He measured the temperature versus time for 15 minutes. The first \( 4.5 \) minutes show the temperature of the acid and base before mixing. The solutions were mixed at the 5 minute mark and the temperature of the resulting salt solution measured for 10 minutes to give the following data. Calculate the \% error between the two results. 2 marks \( \% \) Error \( =( \) Exptl Value \( - \) True Value \( ) \times 100 \% \) divided by True Value \( \% \) Error can be \( + \) or \( - \) depending whether the experimental value is greater or less than the true value.

          Procedure/Obseryations
A student studied the enthalpy of neutralization of \( \mathrm{HNO}_{2} \) and \( \mathrm{NaOH} \) by reacting \( 50.0 \mathrm{~mL} \) of \( 2.00 \mathrm{M} \mathrm{HClO}_{4} \) with \( 50.0 \mathrm{~mL} \) of \( 2.00 \mathrm{M} \mathrm{NaOH} \) in a calorimeter. He measured the temperature versus time for 15 minutes. The first \( 4.5 \) minutes show the temperature of the acid and base before mixing. The solutions were mixed at the 5 minute mark and the temperature of the resulting salt solution measured for 10 minutes to give the following data.
Calculate the \% error between the two results. 2 marks \( \% \) Error \( =( \) Exptl Value \( - \) True Value \( ) \times 100 \% \) divided by True Value \( \% \) Error can be \( + \) or \( - \) depending whether the experimental value is greater or less than the true value.

Procedure/Obseryations
A student studied the enthalpy of neutralization of HNO2 and NaOH by reacting 50.0 mL of 2.00 MHClO4 with 50.0 mL of 2.00 MNaOH in a calorimeter. He measured the temperature versus time for 15 minutes. The first 4.5 minutes show the temperature of the acid and base before mixing. The solutions were mixed at the 5 minute mark and the temperature of the resulting salt solution measured for 10 minutes to give the following data.
Calculate the % error between the two results. 2 marks % Error =( Exptl Value - True Value ) × 100 % divided by True Value % Error can be + or - depending whether the experimental value is greater or less than the true value.

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