Calculate the pH of a solution formed by mixing 500.0 mL of 0.15 M NH4Cl with 400.0 mL of 0.12 M NH3. The Kb for NH3 is 1.8 × 10-5.
Added by Christopher H.
Step 1
First, we need to find the moles of NH4Cl and NH3 in the solution. moles of NH4Cl = 0.15 M * 0.500 L = 0.075 mol moles of NH3 = 0.12 M * 0.400 L = 0.048 mol Show more…
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