00:01
Hello there.
00:01
I see that you have a question on how to calculate ph of solutions containing the four followings that we see right in front of us.
00:11
So let's start with the first one.
00:12
So they want us to find the ph in 0 .005 molarity of hydrochloric acid.
00:23
Oh, drop something on my end.
00:26
Sorry.
00:27
Okay.
00:28
So how we go about this is so i set up like where you balance out the equation and then we set up where the hydrogen equals the hydrochloric acid which is also which is equal to 0 .05 i mean 0 .005 molarity.
00:49
So then we write up the set up for the ph on how to solve it.
00:53
Plug it in and that's how we get the ph for the first one.
00:57
The second one, they want to find us to calculate the ph of the solutions where one litre of 0 .5 molarity of lucene buffer, which has a ph of 9 .6, 2 which is added 1 litre of 0 .1 molarity of sodium hydroxide of sodium hydroxide.
01:30
So how we go about this is that we calculate where we have our weak acid above our weak base.
01:40
And that's our total right there.
01:43
Then same thing.
01:46
Plug it in and i don't know why i keep accidentally writing on it.
01:51
And this is the answer that you will get...