Calculate the rate constant, k, for a reaction at 63.0 °C that has an activation energy of 88.0 kJ/mol and a frequency factor of 7.78 × 10^{11} s^{-1}. k = s^{-1}
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k = A exp(−Ea/(R T)) A = 7.78 × 10^11 s^-1 Ea = 88.0 kJ/mol = 88,000 J/mol T = 63.0 °C = 63.0 + 273.15 = 336.15 K R = 8.314 J/(mol·K) Show more…
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