Calculate the Taylor polynomials T2 and T3 centered at x = a for the given function and value of a. f(x) = x^4 - 2x, a = 4 T2 = ?? T3 = ??
Added by Xavier H.
Step 1
f'(x) = 4x^3 - 2 f''(x) = 12x^2 f'''(x) = 24x Now, we need to evaluate these derivatives at x = a = 4. f(4) = 4^4 - 2(4) = 256 - 8 = 248 f'(4) = 4(4^3) - 2 = 4(64) - 2 = 256 - 2 = 254 f''(4) = 12(4^2) = 12(16) = 192 f'''(4) = 24(4) = 96 Show more…
Show all steps
Close
Your feedback will help us improve your experience
Vincenzo Zaccaro and 84 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Calculate the Taylor polynomials $T_{2}$ and $T_{3}$ centered at $x=a$ for the given function and value of $a .$ $f(x)=x^{2} e^{-x}, \quad a=1$
Infinite Series
Taylor Polynomials
Calculate the Taylor polynomials $T_{2}$ and $T_{3}$ centered at $x=a$ for the given function and value of $a .$ $f(x)=\frac{1}{1+x}, \quad a=2$
Find the Taylor polynomial $T_3(x)$ for the function f centered at the number a. f(x) = x + e⁻ˣ, a = 0
Linda H.
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD