Question

and B by means of four springs and a single dashpot. The stiffness of each spring is 1 kNm?¹. When subjected to a sinusoidal varying force of the form 100 cos 25t (N) the amplitude is 5 mm. Determine the damping coefficient and the amplitude of the force on the support A. (794.9 Nsm?¹, 99.865) $x = 5 mm$ $x_o = \frac{F_o}{Req}$ $x_o = 25 mm$ $x = \frac{F_o}{\sqrt{(k - m\omega^2)^2 + (c\omega)^2}}$ $5 mm^2 = \frac{100^2}{}$ $c = 2\omega m$ $c = 400$

          and B by means of four springs and a single dashpot. The stiffness of each spring is 1 kNm?¹. When subjected to a sinusoidal varying force of the form 100 cos 25t (N) the amplitude is 5 mm. Determine the damping coefficient and the amplitude of the force on the support A. (794.9 Nsm?¹, 99.865)
$x = 5 mm$
$x_o = \frac{F_o}{Req}$
$x_o = 25 mm$
$x = \frac{F_o}{\sqrt{(k - m\omega^2)^2 + (c\omega)^2}}$
$5 mm^2 = \frac{100^2}{}$
$c = 2\omega m$
$c = 400$

and B by means of four springs and a single dashpot. The stiffness of each spring is 1 kNm?¹. When subjected to a sinusoidal varying force of the form 100 cos 25t (N) the amplitude is 5 mm. Determine the damping coefficient and the amplitude of the force on the support A. (794.9 Nsm?¹, 99.865)
x = 5 mm
xo = (Fo)/(Req)
xo = 25 mm
x = (Fo)/(√((k - mω^2)^2 + (cω)^2))
5 mm^2 = (100^2)/()
c = 2ω m
c = 400

Added by Bryan E.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Sri K

04/10/2022

Step 1

The force balance equation for a single degree of freedom system with a mass, damping, and stiffness can be written as: \[ m\ddot{x} + c\dot{x} + kx = F(t) \] Where: - $ m $ = mass - $ c $ = damping coefficient - $ k $ = stiffness - $ x $ = Show more…

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Can someone explain the force balance equation for me as I think I have the wrong Wn and B by means of four springs and a single dashpot. The stiffness of each spring is 1 kNm. When subjected to a sinusoidal varying force of the form 100 cos 25t (N), the amplitude is 5 mm. Determine the damping coefficient and the amplitude of the force on the support A. (794.9 Nsm, 99.865) x = 5 mm 100 cos(25t) F 10 kg MM WM 2haf W X = F Reg X = 25 mm LZW.m Oo+ 25 mm 100?