00:01
We need to find the horizontal and vertical asymptote for the equation 3x square plus x minus 3 by x square plus x minus 6.
00:16
We can analyze the behavior of this function as x approaches infinity or negative infinity as well as the behavior near vertical line.
00:25
To find vertical asymptotes, it occurs when the function approaches infinity or negative infinity.
00:45
So, in order to find that vertical asymptotes, we need to determine the value of x for that this denominator becomes 0.
00:54
When we equate this denominator to 0, we will get function as x minus 2 and x plus 3 is equal to 0.
01:05
When we do this, we will get x is equal to 2 and minus 3.
01:11
These are all the two vertical asymptotes.
01:14
For horizontal asymptotes, to find this, we have to analyze the behavior of function as x approaches in the numerator, we have the highest power of x, we have to analyze that x, which is x square here...