Can someone help me with the step by step mechanism for this...

Can someone help me with the step-by-step mechanism for this? Thank you! DEPC (1.3 eq., NEt(2.7 eq.) 4s2RH 4s2R OH Y3R Y3RY DMF, 0C, 2h -r.t., 14-24h Boc OMe O Boc OMe O Ph 11 S. 79% N-Boc-Dap-Doe 20 Ph 1 N NH*CFCO 1-CFCOH, CHCl, 1.5h 2-DEPC 1.2eq, NEtg2.7eq DMF, 0C, 2h -r.t., 14h 5S 4S BocN 3RCOH Me OMe 7 19 1-CFCOH, CHCl2, 3h BocHN. 2-BroP3.1 eq., iPrNEt 7 eq.) CHCl2, 0C, 2h, r.t., 72h N 3R Me OMe O Me 3F OMe BocN Me Ph Me 72% 55% BocHNS OH N-Boc-Dil-Dap-Doe 21 N-Boc-Val-Dil-Dap-Doe 22 N-Boc-Val 1-CFCOH, CHCl, 4h 2-DEPC (1.3 eq.) N-methylmorpholine (6 eq.) DMF, 0C, 38h Me N'S 3R Me Me Me Me 52% MeC OH Dolastatin 10 Dov

Transcript

00:01 Hi, in this question we are given with this reaction in which h2 react with 2 moles of no to produce n2o plus water.

00:08 We are given with the concentration of h2 and no along with the rate.

00:13 In three trials in this manner, we are asked to give the rate equation an order of reaction for each reactant.

00:22 We can say that the rate is equal to k, that is rate constant, into concentration of h2, to the power of x into concentration of no to the power of y.

00:36 X and y are the order of reactions with respect to h2 and with respect to no respectively.

00:45 In order to find out the value of x and y, we will consider first and second values of concentration of h2, concentration of no, and the rate.

00:58 We can write here as rate 1 divided by rate 2 which is equal to 2 .835 into 10 raise to power minus 3 divided by 1 .134 into 10 raised to power minus 2 equals to k into concentration of h2, that is 0 .35 to the power of x2, that is 0 .35 to the power of x.

01:29 Into concentration of no that is 0 .30 to the power of y divided by k into concentration of h2 that is 0 .35 to the power x into concentration of eno that is 0 .60 to the power y.

01:51 Here we can eliminate the k that is rate constant also 0 .35 to the power x now the on solving this we are getting the value.

02:03 0 .25 is equal to 0 .5 to the power of y.

02:11 We can equate the basis and we can write 0 .25 equals to 0 .25 to the power 2.

02:20 From here we got the value of y that is equal to 2...

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