00:01
In this problem, we are given the two circuits which are shown in case a and b respectively, and the resistors here which are connected, each of them has same value that is r.
00:13
And we are required to determine the equivalent resistance between the points a and b in each case.
00:21
So first we see that in case a, here we take this point as c and this as d and let's simplify the circuit.
00:30
So we have the points a, b and c and d.
00:34
So between a and c we have a resistor.
00:36
Let's connect that.
00:38
Between c and d, we have one resistor.
00:40
Between b and d, we have one resistor.
00:43
Between b and c, we have another resistor, and we have between a and d as well.
00:50
And we have to get the total resistance between a and b.
00:53
So we see that this is a weight stone bridge, and there is no use of this resistor because it does not contribute to total resistance because the current that's flowing through this resistor, that's simply zero.
01:06
And if we just remove this, we see that these two are in series and these two are in series, and we use this expression to get the total resistance of the resistors connected in series.
01:17
So we'll simply add the resistance.
01:20
So we get 2r and 2r resistor, which are in parallel.
01:24
And we use this expression to get the total resistance of the resistors, which are.
01:28
Connected in parallel.
01:30
So we have two resistors each of value 2r and they are in parallel.
01:35
So let's say ra is the equivalent resistance in case a so that will be 1 by 2r plus 1 by 2r...