At least one of the answers above is NOT correct. Find the function $y_1$ of $t$ which is the solution of $121y'' - 154y' + 13y = 0$ with initial conditions $y_1(0) = 1$, $y_1'(0) = 0$. $y_1 = (1 - (13/12))e^{(13t/11)} + (13/12)e^{t/11}$ Find the function $y_2$ of $t$ which is the solution of $121y'' - 154y' + 13y = 0$ with initial conditions $y_2(0) = 0$, $y_2'(0) = 1$. $y_2 = (11/12)e^{(13t/11)} - (11/12)e^{t/11}$ Find the Wronskian $W(t) = W(y_1, y_2)$. $W(t) = (-12/11)e^{(14t/11)}$ Remark: You can find $W$ by direct computation and use Abel's theorem as a check. You should find that $W$ is not zero and so $y_1$ and $y_2$ form a fundamental set of solutions of $121y'' - 154y' + 13y = 0$.
Added by Charles A.
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We can start by assuming a solution of the form y(t) = e^(rt), where r is a constant. Plugging this into the differential equation, we get: 121e^(rt) - 154re^(rt) + 13r^2e^(rt) = 0 Dividing through by e^(rt), we get: 121 - 154r + 13r^2 = 0 This is a quadratic Show more…
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