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Welcome to numerary.
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So for this problem, we are asked to draw out the resonance for this following conjugation.
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So we are going to be looking at what we have here.
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So the resonance, we have hn.
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So this is basically h2n, h2n.
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And what we have here is a resonance.
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So this is going to be connected.
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Like so.
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One, two, three, four.
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And this here will become o minus.
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This is also o minus.
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And we have our double bond here now of o.
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And this will become basically what we have here is that this will become a negative charge because we have the nitrogen loan pair donating into the carbony group.
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Can see and then from there we have cn becomes a double bond with o and then o becomes negative and n becomes n plus all right so this will be plus and this will be negative all right so that's basically what has changed here and then with this we're going to move on to our resonance two so our second residence just put it over here so for our second resonance, we're going to be drawing a similarly.
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So we have h2n, 2, 3, 4.
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And what we have here is going to be the o minus.
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All right.
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And then you see here.
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So we have the negative charge.
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So the carbony, you know, the pi electrons shift into the oxygen.
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Oxygen here...