00:01
Firstly, we will write the given i .e.
00:03
F1 is 8kn, f2 is 9kn, f3 is 12kn and f4 is 6kn.
00:19
So let the resultant force f be.
00:28
So, applying equilibrium condition about x -axis or along x -direction, we will get summation of fx equals to 0.
00:40
So this will be fr -f1 -f2 -f3 -f4 equals to 0.
00:49
So from here we will get fr equals to 35kn.
00:57
So for location on the slab, we will apply the equilibrium condition for moments along x -direction i .e.
01:06
Summation of mx equals to 0.
01:10
So this will be fr multiplied by x -axis minus f1 multiplied by 0, f2 multiplied by 20 minus f3 multiplied by 8 minus f4 multiplied by 20 equals to 0.
01:26
So from here we will get fr multiplied by x minus 180 minus 96 minus 120 equals to 0...