Determine if the point lies on the unit circle. [ left(-frac{sqrt{13}}{8},-frac{sqrt{13}}{8} ight) ] The point ( left(-frac{sqrt{13}}{8},-frac{sqrt{13}}{8} ight) ) is not on the unit circle. The point ( left(-frac{sqrt{13}}{8},-frac{sqrt{13}}{8} ight) ) is on the unit circle.
Added by Ayarpi R.
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We can substitute the given point \(\left(-\frac{\sqrt{13}}{8},-\frac{\sqrt{13}}{8}\right)\) into this equation to see if it holds true. Show more…
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